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0=36x^2-54x-36
We move all terms to the left:
0-(36x^2-54x-36)=0
We add all the numbers together, and all the variables
-(36x^2-54x-36)=0
We get rid of parentheses
-36x^2+54x+36=0
a = -36; b = 54; c = +36;
Δ = b2-4ac
Δ = 542-4·(-36)·36
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8100}=90$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-90}{2*-36}=\frac{-144}{-72} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+90}{2*-36}=\frac{36}{-72} =-1/2 $
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